Optimal. Leaf size=528 \[ \frac{\sqrt{b} \left (15 a^2 C d^2-10 a b d (3 c C-2 B d)+b^2 \left (8 d^2 (A-C)-12 B c d+15 c^2 C\right )\right ) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b \tan (e+f x)}}{\sqrt{b} \sqrt{c+d \tan (e+f x)}}\right )}{4 d^{7/2} f}+\frac{b \left (d^2 (4 A+C)-4 B c d+5 c^2 C\right ) (a+b \tan (e+f x))^{3/2} \sqrt{c+d \tan (e+f x)}}{2 d^2 f \left (c^2+d^2\right )}-\frac{b \sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)} \left (3 (b c-a d) \left (d^2 (4 A+C)-4 B c d+5 c^2 C\right )-4 d^2 ((A-C) (b c-a d)+B (a c+b d))\right )}{4 d^3 f \left (c^2+d^2\right )}-\frac{2 \left (A d^2-B c d+c^2 C\right ) (a+b \tan (e+f x))^{5/2}}{d f \left (c^2+d^2\right ) \sqrt{c+d \tan (e+f x)}}-\frac{(a-i b)^{5/2} (i A+B-i C) \tanh ^{-1}\left (\frac{\sqrt{c-i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a-i b} \sqrt{c+d \tan (e+f x)}}\right )}{f (c-i d)^{3/2}}-\frac{(a+i b)^{5/2} (B-i (A-C)) \tanh ^{-1}\left (\frac{\sqrt{c+i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a+i b} \sqrt{c+d \tan (e+f x)}}\right )}{f (c+i d)^{3/2}} \]
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Rubi [A] time = 8.18832, antiderivative size = 528, normalized size of antiderivative = 1., number of steps used = 15, number of rules used = 9, integrand size = 49, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.184, Rules used = {3645, 3647, 3655, 6725, 63, 217, 206, 93, 208} \[ \frac{\sqrt{b} \left (15 a^2 C d^2-10 a b d (3 c C-2 B d)+b^2 \left (8 d^2 (A-C)-12 B c d+15 c^2 C\right )\right ) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b \tan (e+f x)}}{\sqrt{b} \sqrt{c+d \tan (e+f x)}}\right )}{4 d^{7/2} f}+\frac{b \left (d^2 (4 A+C)-4 B c d+5 c^2 C\right ) (a+b \tan (e+f x))^{3/2} \sqrt{c+d \tan (e+f x)}}{2 d^2 f \left (c^2+d^2\right )}-\frac{b \sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)} \left (3 (b c-a d) \left (d^2 (4 A+C)-4 B c d+5 c^2 C\right )-4 d^2 ((A-C) (b c-a d)+B (a c+b d))\right )}{4 d^3 f \left (c^2+d^2\right )}-\frac{2 \left (A d^2-B c d+c^2 C\right ) (a+b \tan (e+f x))^{5/2}}{d f \left (c^2+d^2\right ) \sqrt{c+d \tan (e+f x)}}-\frac{(a-i b)^{5/2} (i A+B-i C) \tanh ^{-1}\left (\frac{\sqrt{c-i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a-i b} \sqrt{c+d \tan (e+f x)}}\right )}{f (c-i d)^{3/2}}-\frac{(a+i b)^{5/2} (B-i (A-C)) \tanh ^{-1}\left (\frac{\sqrt{c+i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a+i b} \sqrt{c+d \tan (e+f x)}}\right )}{f (c+i d)^{3/2}} \]
Antiderivative was successfully verified.
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Rule 3645
Rule 3647
Rule 3655
Rule 6725
Rule 63
Rule 217
Rule 206
Rule 93
Rule 208
Rubi steps
\begin{align*} \int \frac{(a+b \tan (e+f x))^{5/2} \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right )}{(c+d \tan (e+f x))^{3/2}} \, dx &=-\frac{2 \left (c^2 C-B c d+A d^2\right ) (a+b \tan (e+f x))^{5/2}}{d \left (c^2+d^2\right ) f \sqrt{c+d \tan (e+f x)}}+\frac{2 \int \frac{(a+b \tan (e+f x))^{3/2} \left (\frac{1}{2} (A d (a c+5 b d)+(5 b c-a d) (c C-B d))+\frac{1}{2} d ((A-C) (b c-a d)+B (a c+b d)) \tan (e+f x)+\frac{1}{2} b \left (5 c^2 C-4 B c d+(4 A+C) d^2\right ) \tan ^2(e+f x)\right )}{\sqrt{c+d \tan (e+f x)}} \, dx}{d \left (c^2+d^2\right )}\\ &=-\frac{2 \left (c^2 C-B c d+A d^2\right ) (a+b \tan (e+f x))^{5/2}}{d \left (c^2+d^2\right ) f \sqrt{c+d \tan (e+f x)}}+\frac{b \left (5 c^2 C-4 B c d+(4 A+C) d^2\right ) (a+b \tan (e+f x))^{3/2} \sqrt{c+d \tan (e+f x)}}{2 d^2 \left (c^2+d^2\right ) f}+\frac{\int \frac{\sqrt{a+b \tan (e+f x)} \left (\frac{1}{4} \left (-b (3 b c+a d) \left (5 c^2 C-4 B c d+(4 A+C) d^2\right )+4 a d (A d (a c+5 b d)+(5 b c-a d) (c C-B d))\right )+d^2 \left (2 a b (A c-c C+B d)+a^2 (B c-(A-C) d)-b^2 (B c-(A-C) d)\right ) \tan (e+f x)-\frac{1}{4} b \left (3 (b c-a d) \left (5 c^2 C-4 B c d+(4 A+C) d^2\right )-4 d^2 ((A-C) (b c-a d)+B (a c+b d))\right ) \tan ^2(e+f x)\right )}{\sqrt{c+d \tan (e+f x)}} \, dx}{d^2 \left (c^2+d^2\right )}\\ &=-\frac{2 \left (c^2 C-B c d+A d^2\right ) (a+b \tan (e+f x))^{5/2}}{d \left (c^2+d^2\right ) f \sqrt{c+d \tan (e+f x)}}-\frac{b \left (3 (b c-a d) \left (5 c^2 C-4 B c d+(4 A+C) d^2\right )-4 d^2 ((A-C) (b c-a d)+B (a c+b d))\right ) \sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}}{4 d^3 \left (c^2+d^2\right ) f}+\frac{b \left (5 c^2 C-4 B c d+(4 A+C) d^2\right ) (a+b \tan (e+f x))^{3/2} \sqrt{c+d \tan (e+f x)}}{2 d^2 \left (c^2+d^2\right ) f}+\frac{\int \frac{\frac{1}{8} \left (8 a^3 d^3 (A c-c C+B d)+3 a^2 b d^2 \left (5 c^2 C-8 B c d+(8 A-3 C) d^2\right )+b^3 c \left (15 c^3 C-12 B c^2 d+c (8 A+7 C) d^2-4 B d^3\right )-2 a b^2 d \left (15 c^3 C-10 B c^2 d+3 c (4 A+C) d^2+2 B d^3\right )\right )+d^3 \left (3 a^2 b (A c-c C+B d)-b^3 (A c-c C+B d)+a^3 (B c-(A-C) d)-3 a b^2 (B c-(A-C) d)\right ) \tan (e+f x)+\frac{1}{8} b \left (c^2+d^2\right ) \left (15 a^2 C d^2-10 a b d (3 c C-2 B d)+b^2 \left (15 c^2 C-12 B c d+8 (A-C) d^2\right )\right ) \tan ^2(e+f x)}{\sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}} \, dx}{d^3 \left (c^2+d^2\right )}\\ &=-\frac{2 \left (c^2 C-B c d+A d^2\right ) (a+b \tan (e+f x))^{5/2}}{d \left (c^2+d^2\right ) f \sqrt{c+d \tan (e+f x)}}-\frac{b \left (3 (b c-a d) \left (5 c^2 C-4 B c d+(4 A+C) d^2\right )-4 d^2 ((A-C) (b c-a d)+B (a c+b d))\right ) \sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}}{4 d^3 \left (c^2+d^2\right ) f}+\frac{b \left (5 c^2 C-4 B c d+(4 A+C) d^2\right ) (a+b \tan (e+f x))^{3/2} \sqrt{c+d \tan (e+f x)}}{2 d^2 \left (c^2+d^2\right ) f}+\frac{\operatorname{Subst}\left (\int \frac{\frac{1}{8} \left (8 a^3 d^3 (A c-c C+B d)+3 a^2 b d^2 \left (5 c^2 C-8 B c d+(8 A-3 C) d^2\right )+b^3 c \left (15 c^3 C-12 B c^2 d+c (8 A+7 C) d^2-4 B d^3\right )-2 a b^2 d \left (15 c^3 C-10 B c^2 d+3 c (4 A+C) d^2+2 B d^3\right )\right )+d^3 \left (3 a^2 b (A c-c C+B d)-b^3 (A c-c C+B d)+a^3 (B c-(A-C) d)-3 a b^2 (B c-(A-C) d)\right ) x+\frac{1}{8} b \left (c^2+d^2\right ) \left (15 a^2 C d^2-10 a b d (3 c C-2 B d)+b^2 \left (15 c^2 C-12 B c d+8 (A-C) d^2\right )\right ) x^2}{\sqrt{a+b x} \sqrt{c+d x} \left (1+x^2\right )} \, dx,x,\tan (e+f x)\right )}{d^3 \left (c^2+d^2\right ) f}\\ &=-\frac{2 \left (c^2 C-B c d+A d^2\right ) (a+b \tan (e+f x))^{5/2}}{d \left (c^2+d^2\right ) f \sqrt{c+d \tan (e+f x)}}-\frac{b \left (3 (b c-a d) \left (5 c^2 C-4 B c d+(4 A+C) d^2\right )-4 d^2 ((A-C) (b c-a d)+B (a c+b d))\right ) \sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}}{4 d^3 \left (c^2+d^2\right ) f}+\frac{b \left (5 c^2 C-4 B c d+(4 A+C) d^2\right ) (a+b \tan (e+f x))^{3/2} \sqrt{c+d \tan (e+f x)}}{2 d^2 \left (c^2+d^2\right ) f}+\frac{\operatorname{Subst}\left (\int \left (\frac{b \left (c^2+d^2\right ) \left (15 a^2 C d^2-10 a b d (3 c C-2 B d)+b^2 \left (15 c^2 C-12 B c d+8 (A-C) d^2\right )\right )}{8 \sqrt{a+b x} \sqrt{c+d x}}+\frac{d^3 \left (a^3 (A c-c C+B d)-3 a b^2 (A c-c C+B d)-3 a^2 b (B c-(A-C) d)+b^3 (B c-(A-C) d)\right )+d^3 \left (3 a^2 b (A c-c C+B d)-b^3 (A c-c C+B d)+a^3 (B c-(A-C) d)-3 a b^2 (B c-(A-C) d)\right ) x}{\sqrt{a+b x} \sqrt{c+d x} \left (1+x^2\right )}\right ) \, dx,x,\tan (e+f x)\right )}{d^3 \left (c^2+d^2\right ) f}\\ &=-\frac{2 \left (c^2 C-B c d+A d^2\right ) (a+b \tan (e+f x))^{5/2}}{d \left (c^2+d^2\right ) f \sqrt{c+d \tan (e+f x)}}-\frac{b \left (3 (b c-a d) \left (5 c^2 C-4 B c d+(4 A+C) d^2\right )-4 d^2 ((A-C) (b c-a d)+B (a c+b d))\right ) \sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}}{4 d^3 \left (c^2+d^2\right ) f}+\frac{b \left (5 c^2 C-4 B c d+(4 A+C) d^2\right ) (a+b \tan (e+f x))^{3/2} \sqrt{c+d \tan (e+f x)}}{2 d^2 \left (c^2+d^2\right ) f}+\frac{\operatorname{Subst}\left (\int \frac{d^3 \left (a^3 (A c-c C+B d)-3 a b^2 (A c-c C+B d)-3 a^2 b (B c-(A-C) d)+b^3 (B c-(A-C) d)\right )+d^3 \left (3 a^2 b (A c-c C+B d)-b^3 (A c-c C+B d)+a^3 (B c-(A-C) d)-3 a b^2 (B c-(A-C) d)\right ) x}{\sqrt{a+b x} \sqrt{c+d x} \left (1+x^2\right )} \, dx,x,\tan (e+f x)\right )}{d^3 \left (c^2+d^2\right ) f}+\frac{\left (b \left (15 a^2 C d^2-10 a b d (3 c C-2 B d)+b^2 \left (15 c^2 C-12 B c d+8 (A-C) d^2\right )\right )\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{a+b x} \sqrt{c+d x}} \, dx,x,\tan (e+f x)\right )}{8 d^3 f}\\ &=-\frac{2 \left (c^2 C-B c d+A d^2\right ) (a+b \tan (e+f x))^{5/2}}{d \left (c^2+d^2\right ) f \sqrt{c+d \tan (e+f x)}}-\frac{b \left (3 (b c-a d) \left (5 c^2 C-4 B c d+(4 A+C) d^2\right )-4 d^2 ((A-C) (b c-a d)+B (a c+b d))\right ) \sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}}{4 d^3 \left (c^2+d^2\right ) f}+\frac{b \left (5 c^2 C-4 B c d+(4 A+C) d^2\right ) (a+b \tan (e+f x))^{3/2} \sqrt{c+d \tan (e+f x)}}{2 d^2 \left (c^2+d^2\right ) f}+\frac{\operatorname{Subst}\left (\int \left (\frac{-d^3 \left (3 a^2 b (A c-c C+B d)-b^3 (A c-c C+B d)+a^3 (B c-(A-C) d)-3 a b^2 (B c-(A-C) d)\right )+i d^3 \left (a^3 (A c-c C+B d)-3 a b^2 (A c-c C+B d)-3 a^2 b (B c-(A-C) d)+b^3 (B c-(A-C) d)\right )}{2 (i-x) \sqrt{a+b x} \sqrt{c+d x}}+\frac{d^3 \left (3 a^2 b (A c-c C+B d)-b^3 (A c-c C+B d)+a^3 (B c-(A-C) d)-3 a b^2 (B c-(A-C) d)\right )+i d^3 \left (a^3 (A c-c C+B d)-3 a b^2 (A c-c C+B d)-3 a^2 b (B c-(A-C) d)+b^3 (B c-(A-C) d)\right )}{2 (i+x) \sqrt{a+b x} \sqrt{c+d x}}\right ) \, dx,x,\tan (e+f x)\right )}{d^3 \left (c^2+d^2\right ) f}+\frac{\left (15 a^2 C d^2-10 a b d (3 c C-2 B d)+b^2 \left (15 c^2 C-12 B c d+8 (A-C) d^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{c-\frac{a d}{b}+\frac{d x^2}{b}}} \, dx,x,\sqrt{a+b \tan (e+f x)}\right )}{4 d^3 f}\\ &=-\frac{2 \left (c^2 C-B c d+A d^2\right ) (a+b \tan (e+f x))^{5/2}}{d \left (c^2+d^2\right ) f \sqrt{c+d \tan (e+f x)}}-\frac{b \left (3 (b c-a d) \left (5 c^2 C-4 B c d+(4 A+C) d^2\right )-4 d^2 ((A-C) (b c-a d)+B (a c+b d))\right ) \sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}}{4 d^3 \left (c^2+d^2\right ) f}+\frac{b \left (5 c^2 C-4 B c d+(4 A+C) d^2\right ) (a+b \tan (e+f x))^{3/2} \sqrt{c+d \tan (e+f x)}}{2 d^2 \left (c^2+d^2\right ) f}+\frac{\left ((a+i b)^3 (A+i B-C) (i c+d)\right ) \operatorname{Subst}\left (\int \frac{1}{(i-x) \sqrt{a+b x} \sqrt{c+d x}} \, dx,x,\tan (e+f x)\right )}{2 \left (c^2+d^2\right ) f}+\frac{\left (15 a^2 C d^2-10 a b d (3 c C-2 B d)+b^2 \left (15 c^2 C-12 B c d+8 (A-C) d^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{1-\frac{d x^2}{b}} \, dx,x,\frac{\sqrt{a+b \tan (e+f x)}}{\sqrt{c+d \tan (e+f x)}}\right )}{4 d^3 f}+\frac{\left (d^3 \left (3 a^2 b (A c-c C+B d)-b^3 (A c-c C+B d)+a^3 (B c-(A-C) d)-3 a b^2 (B c-(A-C) d)\right )+i d^3 \left (a^3 (A c-c C+B d)-3 a b^2 (A c-c C+B d)-3 a^2 b (B c-(A-C) d)+b^3 (B c-(A-C) d)\right )\right ) \operatorname{Subst}\left (\int \frac{1}{(i+x) \sqrt{a+b x} \sqrt{c+d x}} \, dx,x,\tan (e+f x)\right )}{2 d^3 \left (c^2+d^2\right ) f}\\ &=\frac{\sqrt{b} \left (15 a^2 C d^2-10 a b d (3 c C-2 B d)+b^2 \left (15 c^2 C-12 B c d+8 (A-C) d^2\right )\right ) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b \tan (e+f x)}}{\sqrt{b} \sqrt{c+d \tan (e+f x)}}\right )}{4 d^{7/2} f}-\frac{2 \left (c^2 C-B c d+A d^2\right ) (a+b \tan (e+f x))^{5/2}}{d \left (c^2+d^2\right ) f \sqrt{c+d \tan (e+f x)}}-\frac{b \left (3 (b c-a d) \left (5 c^2 C-4 B c d+(4 A+C) d^2\right )-4 d^2 ((A-C) (b c-a d)+B (a c+b d))\right ) \sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}}{4 d^3 \left (c^2+d^2\right ) f}+\frac{b \left (5 c^2 C-4 B c d+(4 A+C) d^2\right ) (a+b \tan (e+f x))^{3/2} \sqrt{c+d \tan (e+f x)}}{2 d^2 \left (c^2+d^2\right ) f}+\frac{\left ((a-i b)^3 (i A+B-i C)\right ) \operatorname{Subst}\left (\int \frac{1}{-a+i b-(-c+i d) x^2} \, dx,x,\frac{\sqrt{a+b \tan (e+f x)}}{\sqrt{c+d \tan (e+f x)}}\right )}{(c-i d) f}+\frac{\left ((a+i b)^3 (A+i B-C) (i c+d)\right ) \operatorname{Subst}\left (\int \frac{1}{a+i b-(c+i d) x^2} \, dx,x,\frac{\sqrt{a+b \tan (e+f x)}}{\sqrt{c+d \tan (e+f x)}}\right )}{\left (c^2+d^2\right ) f}\\ &=-\frac{(a-i b)^{5/2} (i A+B-i C) \tanh ^{-1}\left (\frac{\sqrt{c-i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a-i b} \sqrt{c+d \tan (e+f x)}}\right )}{(c-i d)^{3/2} f}-\frac{(a+i b)^{5/2} (B-i (A-C)) \tanh ^{-1}\left (\frac{\sqrt{c+i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a+i b} \sqrt{c+d \tan (e+f x)}}\right )}{(c+i d)^{3/2} f}+\frac{\sqrt{b} \left (15 a^2 C d^2-10 a b d (3 c C-2 B d)+b^2 \left (15 c^2 C-12 B c d+8 (A-C) d^2\right )\right ) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b \tan (e+f x)}}{\sqrt{b} \sqrt{c+d \tan (e+f x)}}\right )}{4 d^{7/2} f}-\frac{2 \left (c^2 C-B c d+A d^2\right ) (a+b \tan (e+f x))^{5/2}}{d \left (c^2+d^2\right ) f \sqrt{c+d \tan (e+f x)}}-\frac{b \left (3 (b c-a d) \left (5 c^2 C-4 B c d+(4 A+C) d^2\right )-4 d^2 ((A-C) (b c-a d)+B (a c+b d))\right ) \sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}}{4 d^3 \left (c^2+d^2\right ) f}+\frac{b \left (5 c^2 C-4 B c d+(4 A+C) d^2\right ) (a+b \tan (e+f x))^{3/2} \sqrt{c+d \tan (e+f x)}}{2 d^2 \left (c^2+d^2\right ) f}\\ \end{align*}
Mathematica [C] time = 44.2267, size = 1653959, normalized size = 3132.5 \[ \text{Result too large to show} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 180., size = 0, normalized size = 0. \begin{align*} \int{(A+B\tan \left ( fx+e \right ) +C \left ( \tan \left ( fx+e \right ) \right ) ^{2}) \left ( a+b\tan \left ( fx+e \right ) \right ) ^{{\frac{5}{2}}} \left ( c+d\tan \left ( fx+e \right ) \right ) ^{-{\frac{3}{2}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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